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Molecular Basis of Inheritance: Class-XII


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MCQs on Molecular Basis of Inheritance: Class-XII for NEET Practice


Match List-I with List-II regarding HGP methodologies.

List-I (Method)List-II (Description)
A. Expressed Sequence Tags (ESTs)I. Sequencing the whole genome (coding and non-coding)
B. Sequence AnnotationII. Identifying genes expressed as RNA
C. BAC/YACIII. Automated DNA sequencing principle
D. Sanger MethodIV. Vectors for cloning large DNA fragments

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-I, C-IV, D-III
  • A-I, B-II, C-IV, D-III
  • A-II, B-I, C-III, D-IV
  • A-III, B-IV, C-I, D-II
  • Correct Option: A  [ A-II, B-I, C-IV, D-III ]

    Remark: ESTs focus on sequencing genes expressed as RNA. Sequence Annotation involves sequencing the entire genome and assigning functions. BAC (Bacterial Artificial Chromosome) and YAC (Yeast Artificial Chromosome) are vectors. The Sanger Method is the principle used for automated DNA sequencing.

Match List-I with List-II regarding DNA Fingerprinting terms.

List-I (Term)List-II (Definition)
A. VNTRI. Separation of DNA based on size
B. ProbeII. Variable Number of Tandem Repeats (Mini-satellite)
C. Southern BlottingIII. Radioactive single-stranded DNA for detection
D. Gel ElectrophoresisIV. Transfer of DNA to synthetic membrane

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-III, C-IV, D-I
  • A-II, B-I, C-IV, D-III
  • A-III, B-II, C-IV, D-I
  • A-I, B-II, C-III, D-IV
  • Correct Option: A  [ A-II, B-III, C-IV, D-I ]

    Remark: VNTRs are mini-satellite sequences used as markers. A Probe is a radioactive single-stranded DNA sequence. Southern Blotting transfers DNA from gel to membrane. Gel Electrophoresis separates DNA fragments by size.

Match List-I with List-II regarding Genome sizes.

List-I (Organism)List-II (Size)
A. Bacteriophage Phi X 174I. 4.6 x 10^6 bp
B. Bacteriophage LambdaII. 3.3 x 10^9 bp
C. E. coliIII. 5386 nucleotides
D. Human (Haploid)IV. 48502 bp

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-III, B-IV, C-I, D-II
  • A-III, B-I, C-IV, D-II
  • A-IV, B-III, C-I, D-II
  • A-I, B-II, C-III, D-IV
  • Correct Option: A  [ A-III, B-IV, C-I, D-II ]

    Remark: Phi X 174 has 5386 nucleotides (ssDNA). Lambda phage has 48502 bp. E. coli has 4.6 million bp. Haploid human genome is 3.3 billion bp.

Match List-I with List-II regarding Bonds in Biomolecules.

List-I (Bond)List-II (Location)
A. N-Glycosidic bondI. Between adjacent nucleotides
B. Phosphodiester bondII. Between complementary bases
C. Hydrogen bondIII. Between Sugar and Nitrogenous Base
D. Peptide bondIV. Between Amino acids

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-III, B-I, C-II, D-IV
  • A-III, B-II, C-I, D-IV
  • A-I, B-III, C-II, D-IV
  • A-II, B-I, C-IV, D-III
  • Correct Option: A  [ A-III, B-I, C-II, D-IV ]

    Remark: N-Glycosidic bonds link the base to sugar. Phosphodiester bonds link nucleotides in the backbone. Hydrogen bonds link base pairs. Peptide bonds link amino acids.

Match List-I with List-II regarding Codons.

List-I (Codon)List-II (Function/Amino Acid)
A. AUGI. Stop Codon (Ochre)
B. UAAII. Phenylalanine
C. UUUIII. Start Codon, Methionine
D. UGAIV. Stop Codon (Opal)

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-III, B-I, C-II, D-IV
  • A-III, B-II, C-I, D-IV
  • A-I, B-III, C-II, D-IV
  • A-II, B-I, C-III, D-IV
  • Correct Option: A  [ A-III, B-I, C-II, D-IV ]

    Remark: AUG is the Start Codon (Methionine). UAA and UGA are Stop Codons. UUU codes for Phenylalanine.

Match List-I with List-II regarding RNA types.

List-I (RNA)List-II (Role)
A. mRNAI. Structural and catalytic role
B. tRNAII. Template for protein synthesis
C. rRNAIII. Adapter molecule
D. hnRNAIV. Precursor to mRNA

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-III, C-I, D-IV
  • A-I, B-II, C-III, D-IV
  • A-III, B-II, C-I, D-IV
  • A-II, B-I, C-IV, D-III
  • Correct Option: A  [ A-II, B-III, C-I, D-IV ]

    Remark: mRNA is the template. tRNA is the adapter. rRNA is structural/catalytic. hnRNA is the primary transcript precursor.

Match List-I with List-II regarding Nitrogenous Bases.

List-I (Base)List-II (Description)
A. AdenineI. Pyrimidine in DNA and RNA
B. CytosineII. Purine
C. ThymineIII. Pyrimidine in DNA only (5-methyl uracil)
D. UracilIV. Pyrimidine in RNA only

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-I, C-III, D-IV
  • A-III, B-I, C-IV, D-II
  • A-I, B-III, C-IV, D-II
  • A-IV, B-I, C-III, D-II
  • Correct Option: A  [ A-II, B-I, C-III, D-IV ]

    Remark: Adenine is a Purine. Cytosine is a Pyrimidine in both nucleic acids. Thymine is in DNA only. Uracil is in RNA only.

Match List-I with List-II regarding Scientists.

List-I (Scientist)List-II (Work)
A. Alec JeffreysI. Lac Operon
B. Frederick SangerII. DNA Sequencing
C. Jacob & MonodIII. DNA Fingerprinting
D. Har Gobind KhoranaIV. Artificial synthesis of RNA

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-III, B-II, C-I, D-IV
  • A-III, B-I, C-IV, D-II
  • A-II, B-IV, C-I, D-III
  • A-IV, B-III, C-II, D-I
  • Correct Option: A  [ A-III, B-II, C-I, D-IV ]

    Remark: Jeffreys developed Fingerprinting. Sanger developed Sequencing. Jacob & Monod elucidated Lac Operon. Khorana synthesized RNA homopolymers/copolymers.

Match List-I with List-II regarding DNA Forms.

List-I (DNA Form)List-II (Characteristic)
A. B-DNAI. Left-handed helix
B. Z-DNAII. Most common, Right-handed
C. A-DNAIII. Dehydrated form, Right-handed

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-I, C-III
  • A-I, B-II, C-III
  • A-II, B-III, C-I
  • A-III, B-II, C-I
  • Correct Option: A  [ A-II, B-I, C-III ]

    Remark: B-DNA is the standard Watson-Crick right-handed helix. Z-DNA is a left-handed helix. A-DNA is a right-handed form observed under dehydration.

Match List-I with List-II regarding Genetic Code Deciphering.

List-I (Scientist)List-II (Contribution)
A. George GamowI. Cell-free system for protein synthesis
B. Marshall NirenbergII. Proposed triplet code
C. Severo OchoaIII. Polynucleotide Phosphorylase enzyme

[Molecular-Basis-of-Inheritance] [class-xii ]

  • A-II, B-I, C-III
  • A-I, B-II, C-III
  • A-II, B-III, C-I
  • A-III, B-II, C-I
  • Correct Option: A  [ A-II, B-I, C-III ]

    Remark: Gamow proposed the triplet nature. Nirenberg developed the cell-free system. Severo Ochoa discovered the enzyme for template-independent RNA synthesis.