III. No change in reading frame (Amino acid deleted)
D. Silent Mutation
IV. No change in amino acid sequence
Point mutation involves a single base change, such as in Sickle Cell Anemia (GAG to GUG). Insertion of 1 base causes a Frame shift. Deletion of 3 bases removes a whole codon/amino acid but does not shift the reading frame. Silent mutations result in no change to the amino acid sequence,,.
Question 662 of 668
📘 CLASS XII
Match List-I with List-II regarding Satellite DNA types.
List-I (Type)
List-II (Characteristics)
A. Satellite DNA
I. VNTRs (0.1 to 20 kb size)
B. Mini-satellite
II. Bulk of repetitive DNA (peaks in centrifugation)
C. Micro-satellite
III. STRs (Short Tandem Repeats, very small)
Satellite DNA forms the bulk of repetitive DNA and appears as separate peaks in density centrifugation. Mini-satellites correspond to VNTRs (0.1-20 kb). Micro-satellites correspond to STRs (Short Tandem Repeats),,.
Question 663 of 668
📘 CLASS XII
Match List-I with List-II regarding Codons and their functions.
List-I (Codon)
List-II (Function/Amino Acid)
A. AUG
I. Stop Codon (Ochre/Amber/Opal)
B. UUU
II. Phenylalanine
C. UAA, UAG, UGA
III. Start Codon, Methionine
AUG is the Start codon and codes for Methionine. UUU codes for Phenylalanine. UAA, UAG, and UGA are the three Stop codons,.
Question 664 of 668
📘 CLASS XII
Match List-I with List-II regarding HGP Data.
List-I (Feature)
List-II (Data)
A. Chromosome 1
I. Fewest genes (231)
B. Chromosome Y
II. Largest gene (2.4 million bases)
C. Dystrophin Gene
III. Most genes (2968)
D. Protein coding genome
IV. Less than 2 percent
Chromosome 1 has the most genes (2968). Chromosome Y has the fewest genes (231). The Dystrophin gene is the largest with 2.4 million base pairs. Less than 2% of the genome codes for proteins,.
Question 665 of 668
📘 CLASS XII
Match List-I with List-II regarding Lac Operon Components.
List-I (Component)
List-II (Function)
A. Inducer (Lactose)
I. Binding site for RNA Polymerase
B. Repressor
II. Binds to Operator to block transcription
C. Operator
III. Binding site for Repressor
D. Promoter
IV. Binds to Repressor to inactivate it
Lactose acts as the Inducer by binding to the Repressor and inactivating it. The Repressor protein normally binds to the Operator region to block transcription. The Operator is the specific binding site for the Repressor. The Promoter is where RNA Polymerase binds,.
Question 666 of 668
📘 CLASS XII
Match List-I with List-II regarding DNA Packaging.
List-I (Component)
List-II (Description)
A. Histone Octamer
I. Linker histone
B. H1 Histone
II. Core of 8 molecules (H2A, H2B, H3, H4)
C. Euchromatin
III. Densely packed, transcriptionally inactive
D. Heterochromatin
IV. Loosely packed, transcriptionally active
The Histone Octamer is the core unit of the nucleosome (8 molecules). H1 Histone acts as the linker. Euchromatin is loosely packed and active. Heterochromatin is densely packed and inactive,,.
Question 667 of 668
📘 CLASS XII
Match List-I with List-II regarding DNA Dimensions.
List-I (Dimension)
List-II (Value)
A. Pitch of Helix
I. 0.34 nm
B. Distance between base pairs
II. 3.4 nm (34 Angstrom)
C. Base pairs per turn
III. 2.2 meters
D. Length of DNA in human cell
IV. 10
The pitch of the DNA helix is 3.4 nm. The distance between base pairs is 0.34 nm. There are 10 base pairs per turn. The length of DNA in a human diploid cell is approx 2.2 meters,.
Question 668 of 668
📘 CLASS XII
Match List-I with List-II regarding Transcription Unit.
List-I (Part)
List-II (Description)
A. Promoter
I. Located at 5-prime end (upstream) of coding strand
B. Terminator
II. Strand with same sequence as RNA (except T/U)
C. Coding Strand
III. Located at 3-prime end (downstream) of coding strand
D. Template Strand
IV. Strand with 3-prime to 5-prime polarity
The Promoter is located at the 5-prime end (upstream). The Terminator is at the 3-prime end (downstream). The Coding Strand has the same sequence as RNA. The Template Strand has 3-prime to 5-prime polarity and guides synthesis,.
