Match List-I with List-II regarding Nucleosome packaging.
List-I (Component)
List-II (Description)
A. Histone Octamer
I. Linker protein sealing DNA entry/exit
B. DNA
II. Basic amino acids rich in Histones
C. H1 Histone
III. Negatively charged polymer
D. Lysine and Arginine
IV. Core of 8 molecules (H2A, H2B, H3, H4)
The Histone Octamer is the core of the nucleosome, formed by two copies each of H2A, H2B, H3, and H4. DNA is the negatively charged polymer (due to phosphate groups) that wraps around the octamer. H1 Histone is the linker histone that binds to the linker DNA where it enters and leaves the nucleosome. Lysine and Arginine are the positively charged basic amino acids abundant in histones.
Question 592 of 668
📘 CLASS XII
Match List-I with List-II regarding Chromatin types.
List-I (Type)
List-II (Property)
A. Euchromatin
I. Densely packed, Transcriptionally Inactive
B. Heterochromatin
II. Loosely packed, Transcriptionally Active
C. Nucleosome
III. Unit of chromatin ("Beads-on-string")
D. Non-histone Chromosomal Proteins
IV. Proteins for higher-level packaging
Euchromatin is loosely packed, stains lightly, and is transcriptionally active. Heterochromatin is densely packed, stains darkly, and is transcriptionally inactive. The Nucleosome is the repeating unit of chromatin, giving the "beads-on-string" appearance. Non-histone Chromosomal (NHC) proteins are required for the packaging of chromatin at higher levels.
Question 593 of 668
📘 CLASS XII
Match List-I with List-II regarding the Hershey-Chase Experiment.
List-I (Component)
List-II (Label/Role)
A. Radioactive Sulfur (S-35)
I. Used to label DNA
B. Radioactive Phosphorus (P-32)
II. Removal of viral coats (Agitation)
C. Blending
III. Used to label Protein coat
D. Centrifugation
IV. Separation of virus from bacteria based on density
Radioactive Sulfur (S-35) labels the protein coat because amino acids (Methionine, Cysteine) contain sulfur, but DNA does not. Radioactive Phosphorus (P-32) labels DNA because the backbone contains phosphates. Blending is the agitation step to shear off viral coats. Centrifugation separates the heavier bacterial pellet (containing DNA) from the lighter viral supernatant.
Question 594 of 668
📘 CLASS XII
Match List-I with List-II regarding DNA Replication Enzymes.
List-I (Enzyme)
List-II (Function)
A. Helicase
I. Relieves supercoiling/tension
B. Topoisomerase (DNA Gyrase)
II. Synthesizes RNA primer
C. Primase
III. Unzips/Unwinds DNA helix
D. DNA Ligase
IV. Joins Okazaki fragments (Molecular Glue)
Helicase unwinds the DNA double helix by breaking hydrogen bonds. Topoisomerase relieves the torsional strain/supercoiling ahead of the replication fork. Primase synthesizes the short RNA primer needed for DNA polymerase to start. DNA Ligase joins the discontinuous Okazaki fragments on the lagging strand.
Question 595 of 668
📘 CLASS XII
Match List-I with List-II regarding Transcription Units.
List-I (Part)
List-II (Characteristic)
A. Promoter
I. Located at 5-prime end (upstream) of coding strand
B. Terminator
II. Strand with 3-prime to 5-prime polarity
C. Coding Strand
III. Located at 3-prime end (downstream) of coding strand
D. Template Strand
IV. Sequence same as RNA (except T instead of U)
The Promoter is located upstream at the 5-prime end of the coding strand. The Terminator is downstream at the 3-prime end. The Coding Strand runs 5-prime to 3-prime and has the same sequence as RNA (T replacing U). The Template Strand has 3-prime to 5-prime polarity and guides the synthesis.
Question 596 of 668
📘 CLASS XII
Match List-I with List-II regarding Eukaryotic RNA Polymerases.
List-I (Enzyme)
List-II (Transcript)
A. RNA Polymerase I
I. hnRNA (Precursor of mRNA)
B. RNA Polymerase II
II. tRNA, 5S rRNA, snRNA
C. RNA Polymerase III
III. rRNAs (28S, 18S, 5.8S)
In eukaryotes, RNA Polymerase I transcribes large rRNAs (28S, 18S, 5.8S). RNA Polymerase II transcribes hnRNA, which is processed into mRNA. RNA Polymerase III transcribes tRNA, 5S rRNA, and snRNAs. Mnemonic: I-rRNA, II-mRNA, III-tRNA (RMT).
Question 597 of 668
📘 CLASS XII
Match List-I with List-II regarding RNA Processing.
List-I (Process)
List-II (Details)
A. Capping
I. Removal of Introns and joining of Exons
B. Tailing
II. Addition of Methyl Guanosine Triphosphate at 5-prime end
C. Splicing
III. Addition of Adenylate residues at 3-prime end
D. Exons
IV. Coding sequences that appear in mature RNA
Capping adds a 7-methylguanosine cap to the 5-prime end. Tailing adds a Poly-A tail (Adenylate residues) to the 3-prime end. Splicing removes non-coding Introns. Exons are the coding sequences retained in the mature mRNA.
Question 598 of 668
📘 CLASS XII
Match List-I with List-II regarding Genetic Code properties.
List-I (Property)
List-II (Explanation)
A. Degeneracy
I. One codon codes for only one amino acid
B. Unambiguous
II. Code is read continuously without punctuation
C. Universal
III. One amino acid can be coded by multiple codons
D. Comma-less
IV. Code is nearly same in all organisms (bacteria to human)
Degeneracy means some amino acids are coded by more than one codon. Unambiguous means a codon codes for one specific amino acid only. Universal means the code is shared by almost all organisms. Comma-less means the code is read contiguously.
Question 599 of 668
📘 CLASS XII
Match List-I with List-II regarding Translation.
List-I (Component)
List-II (Function)
A. Aminoacyl-tRNA Synthetase
I. Formation of peptide bond (Ribozyme)
B. 23S rRNA
II. Termination of translation
C. Release Factor
III. Charging of tRNA (Aminoacylation)
D. UTR
IV. Required for efficient translation
Aminoacyl-tRNA synthetase charges tRNA with amino acids. 23S rRNA acts as a ribozyme (peptidyl transferase) in bacteria. Release factors bind to stop codons to end translation. UTRs (Untranslated Regions) improve the efficiency of translation.
Question 600 of 668
📘 CLASS XII
Match List-I with List-II regarding Lac Operon genes.
List-I (Gene)
List-II (Product)
A. i gene
I. Beta-galactosidase
B. z gene
II. Repressor Protein
C. y gene
III. Transacetylase
D. a gene
IV. Permease
The i gene codes for the Repressor. The z gene codes for Beta-galactosidase (hydrolyzes lactose). The y gene codes for Permease (increases permeability). The a gene codes for Transacetylase.