In eukaryotes, RNA Polymerase I transcribes large rRNAs (28S, 18S, 5.8S). RNA Polymerase II transcribes hnRNA (heterogeneous nuclear RNA), which processes into mRNA. RNA Polymerase III transcribes tRNA, 5S rRNA, and snRNAs. A mnemonic is RMT (I->rRNA, II->mRNA, III->tRNA).
Question 532 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (RNA Processing)
List-II (Process)
A. Capping
I. Removal of Introns
B. Tailing
II. Addition of 7-methylguanosine
C. Splicing
III. Addition of Adenylate residues
D. Exons
IV. Coding sequences joined together
Capping involves adding a 7-methylguanosine cap to the 5-prime end of hnRNA. Tailing involves adding a Poly-A tail (Adenylate residues) to the 3-prime end. Splicing is the removal of non-coding Introns. Exons are the coding sequences that are joined together to form the mature mRNA.
Question 533 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (Genetic Code)
List-II (Feature)
A. Degenerate
I. Code is contiguous (no punctuation)
B. Unambiguous
II. Multiple codons for one amino acid
C. Universal
III. One codon codes for only one amino acid
D. Comma-less
IV. Same code in bacteria and humans
Degenerate means that some amino acids are coded by more than one codon (redundancy). Unambiguous means a specific codon always codes for the same specific amino acid. Universal means the code applies to nearly all organisms. Comma-less means the code is read continuously without pauses or punctuation.
Question 534 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (tRNA Structure)
List-II (Description)
A. Anticodon Loop
I. Shape of 2D structure
B. Acceptor Arm (3-prime)
II. Binds to mRNA codon
C. Clover-leaf
III. Binds to Amino Acid
D. Inverted L
IV. Shape of 3D structure
The Anticodon loop contains bases complementary to the mRNA codon. The 3-prime Acceptor Arm binds to the specific amino acid. The 2D secondary structure resembles a Clover-leaf. The actual 3D tertiary structure resembles an Inverted L.
Question 535 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (Translation)
List-II (Function)
A. Aminoacyl-tRNA Synthetase
I. Formation of Peptide bond
B. 23S rRNA (Ribozyme)
II. Terminates translation
C. Release Factor
III. Activation and charging of tRNA
D. UTR (Untranslated Region)
IV. Efficiency of translation
Aminoacyl-tRNA Synthetase activates amino acids and links them to tRNA (charging). The 23S rRNA in bacteria acts as a Ribozyme (Peptidyl transferase) to form peptide bonds. Release Factors bind to stop codons to terminate the process. UTRs are regions before the start and after the stop codon that improve the efficiency of translation.
Question 536 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (Lac Operon Genes)
List-II (Protein Product)
A. i gene
I. Beta-galactosidase
B. z gene
II. Repressor
C. y gene
III. Transacetylase
D. a gene
IV. Permease
The i gene codes for the Repressor protein. The z gene codes for Beta-galactosidase (breaks down lactose). The y gene codes for Permease (transports lactose into cell). The a gene codes for Transacetylase.
Question 537 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (Lac Operon Regulation)
List-II (Role)
A. Inducer (Lactose)
I. Binding site for RNA Polymerase
B. Repressor
II. Binds to Operator to block transcription
C. Operator
III. Binding site for Repressor
D. Promoter
IV. Binds to Repressor to inactivate it
Lactose acts as the Inducer by binding to the Repressor and inactivating it. The Repressor protein normally binds to the Operator region to physically block transcription. The Operator is the specific DNA sequence where the Repressor binds. The Promoter is the sequence where RNA Polymerase binds to initiate transcription.
Question 538 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (HGP Methodologies)
List-II (Description)
A. Expressed Sequence Tags (ESTs)
I. Sequencing both coding and non-coding regions
B. Sequence Annotation
II. Identifying genes expressed as RNA
C. BAC / YAC
III. Automated DNA sequencing method
D. Sanger Method
IV. Vectors for cloning large DNA fragments
Expressed Sequence Tags (ESTs) involve sequencing only the genes that are expressed as RNA. Sequence Annotation involves sequencing the whole genome (coding and non-coding) and assigning functions later. BAC (Bacterial Artificial Chromosome) and YAC (Yeast Artificial Chromosome) are vectors used to clone large DNA fragments. The Sanger Method is the principle behind automated DNA sequencing.
Question 539 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (HGP Findings)
List-II (Details)
A. Total base pairs (Haploid)
I. Less than 2 percent
B. Protein coding genome
II. 3.3 Billion (approx)
C. Largest Gene
III. Chromosome 1
D. Most Genes (2968)
IV. Dystrophin (2.4 million bases)
The human haploid genome contains approximately 3.3 billion base pairs (specifically 3.1647 billion). Less than 2% of the genome codes for proteins. The largest known human gene is Dystrophin, spanning 2.4 million bases. Chromosome 1 has the highest number of genes (2968).
Question 540 of 668
📘 CLASS XII
Match List-I with List-II.
List-I (DNA Fingerprinting Steps)
List-II (Action)
A. Digestion
I. Transfer DNA to Nitrocellulose membrane
B. Gel Electrophoresis
II. Separation of DNA fragments by size
C. Southern Blotting
III. Cutting DNA with Restriction Endonucleases
D. Hybridization
IV. Using labeled VNTR probes
Digestion refers to cutting DNA into fragments using restriction enzymes. Gel Electrophoresis separates these fragments based on size (smaller fragments move faster). Southern Blotting is the transfer of these separated fragments onto a synthetic membrane like nitrocellulose. Hybridization involves binding radioactive VNTR probes to specific complementary DNA sequences on the membrane.