Year-wise Biology practice

NEET (Oct)2020 Biology PYQs

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89 questions in this collection ยท Page 4 of 9

Question 31 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Plant Growth And Development

Inhibitory substances in dormant seeds cannot be removed by subjecting seeds to:
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Question 32 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Plant Growth And Development

Match the following concerning the activity/function and the phytohormone involved:
(A)Fruit ripener (I)Abscisic acid
(B)Herbicide (II)GA3
(C)Bolting agent (III)2, 4-D
(D)Stress hormone (IV)Ethephon
Select the correct option from following:
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Question 33 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Plant Growth And Development

A species which was introduced for ornamentation but has become a trouble-some weed in India:
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Question 34 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Digestion And Absorption

Intrinsic factor that helps in the absorption of vitamin B12 is secreted by:
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Question 35 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Digestion And Absorption

The proteolytic enzyme rennin is found in:
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Question 36 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Breathing And Exchange Of Gases

The Total Lung Capacity (TLC) is the total volume of air accomodated in the lungs at the end of a forced inspiration. This includes:
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Question 37 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Breathing And Exchange Of Gases

Match the following columns and select the correct option :
Column-I Column-II
(A)Pneumotaxic Centre (I)Alveoli
(B)O2 Dissociation curve (II) Pons region of brain
(C)Carbonic Anhydrase (III)Haemoglobin
(D)Primary site of exchange of gases (IV)R.B.C.
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Question 38 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Breathing And Exchange Of Gases

According to Central Pollution Control Board [CPCB] what size (in diameter) of particulate is responsible for causing greater harm to human health ?

AI-generated explanation. Check against your textbook.

Explanation:

PM2.5 (particulate matter with diameter 2.5 ฮผm or less) is most harmful because it can penetrate deep into the lungs and even enter the bloodstream. According to CPCB guidelines, these tiny particles cause greater health effects than larger particles. Thus, option 2 (2.5 micrometers) is correct. Larger particles like 3.0โ€“4.0 ฮผm (options 1, 3, 4) are more likely to lodge in the nose or throat and are less able to reach deep lung tissues, causing comparatively milder effects.

๐Ÿง  Did You Know?

NCERT explains that finer particles, especially PM2.5, pose serious health risks, including respiratory and cardiovascular problems.

๐Ÿ’ก NCERT Memory Line:

PM2.5 refers to particulates with diameter 2.5 ฮผm or less, capable of reaching deep lungs and entering the bloodstream, causing greater health impacts.

Question 39 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Body Fluids And Circulation

Which of the following conditions cause erythroblastosis foetalis ?
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Question 40 of 89
๐ŸŸข NEET (Oct)2020 ๐Ÿ“˜ CLASS XI

Excretory Products And Their Elimination

The increase in osmolarity from outer to inner medullary interstitium is maintained due to:
I. Close proximity between Henle's loop and vasa recta
II. Counter current mechanism
III. Selective secretion of HCO3- and hydrogen ions in PCT
IV. Higher blood pressure in glomerular capillaries

AI-generated explanation. Check against your textbook.

Explanation:

The osmolarity of the renal medulla increases from outer to inner due to the countercurrent mechanism involving the loop of Henle and the vasa recta. This is achieved mainly because of their close proximity and interaction (I and II). Options III and IV are not the primary reasons for this gradient: III refers to secretion in the proximal convoluted tubule, which relates to acid-base balance, not medullary osmolarity; IV (high glomerular blood pressure) does not establish the medullary osmotic gradient. Therefore, the correct combination is I and II.

๐Ÿง  Did You Know?

NCERT explains that the countercurrent mechanism in the loop of Henle and the surrounding vasa recta creates and preserves the medullary osmotic gradient essential for water reabsorption.

๐Ÿ’ก NCERT Memory Line:

Countercurrent mechanism and close interaction of loop of Henle with vasa recta maintain increasing osmolarity from outer to inner medulla.

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