Class XII Biology
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519 questions in this chapter
Question 361 of 519
π CLASS XII
Match List-I (Genetic Development Stage) with List-II (Key Concept/Finding):
List-I
List-II
A. Mendelβs Factors
I. Units of inheritance (before physical identity was known)
B. Chromosomes
II. Physical basis of gene segregation (discovered c. 1900)
C. Double Helix
III. Structural basis of genetic material (DNA)
D. Molecular Biology
IV. Consequent development focusing on genotype/phenotype conversion structure
Choose the correct answer from the options given below:
Mendelβs factors were the original term for units of inheritance. Chromosomes were discovered around 1900 and provided the physical basis for segregation. The double helix provided the structural basis of DNA. Molecular biology grew consequently from the attempt to understand the nature of factors.
Question 362 of 519
π CLASS XII
Match List-I (Thalassemia Type) with List-II (Gene Control/Location):
List-I
List-II
A. $\alpha$ Thalassemia
I. Production of $\alpha$ globin chain affected
B. $\beta$ Thalassemia
II. Production of $\beta$ globin chain affected
C. Genes controlling $\alpha$ Thalassemia
III. HBA1 and HBA2 genes on chromosome 16
D. Gene controlling $\beta$ Thalassemia
IV. HBB gene on chromosome 11
Choose the correct answer from the options given below:
In $\alpha$ Thalassemia, $\alpha$ globin chain production is affected. In $\beta$ Thalassemia, $\beta$ globin chain production is affected. $\alpha$ Thalassemia is controlled by two genes (HBA1 and HBA2) on chromosome 16. $\beta$ Thalassemia is controlled by a single gene (HBB) on chromosome 11.
Question 363 of 519
π CLASS XII
Match List-I (Mendelian/Genetic Study) with List-II (Methodology/Approach):
List-I
List-II
A. Mendelβs investigation approach
I. Applied statistical analysis and mathematical logic
B. Calculating offspring probability
II. Punnett Square
C. Determining unknown dominant genotype
III. Test Cross (crossing with recessive parent)
D. Studying human inheritance
IV. Pedigree Analysis
Choose the correct answer from the options given below:
Mendel applied statistical analysis and mathematical logic. Punnett Square is used to calculate offspring probability. Test cross determines an unknown dominant genotype by crossing with the recessive parent. Pedigree analysis is used to trace human inheritance patterns.
Question 364 of 519
π CLASS XII
Match List-I (Chromosomal Movement) with List-II (Mendelian Parallel):
List-I (Chromosome Behavior)
List-II (Gene Behavior)
A. Chromosomes occur in pairs
I. Factors occur in pairs
B. Segregation during gamete formation (Meiosis)
II. Only one allele of a pair is transmitted to a gamete
C. Two chromosome pairs align independently at Metaphase I
III. One gene pair segregates independently of another pair
D. Pairing and separation of chromosomes
IV. Leads to segregation of factors they carried
Choose the correct answer from the options given below:
Sutton and Boveri noted that chromosomes (A) occur in pairs, parallel to Mendel's factors (I). Chromosome segregation (B) means only one is transmitted to a gamete (II). Independent alignment of chromosomes (C) is the basis for the independent segregation of gene pairs (III). The separation of chromosomes (D) leads to factor segregation (IV).
Question 365 of 519
π CLASS XII
Match List-I (Phenotypic Result) with List-II (Dominance/Blending Interpretation):
List-I
List-II
A. F1 progeny (Tall x Dwarf) are all Tall
I. Law of Dominance
B. F2 progeny shows both Tall and Dwarf traits (3:1)
II. Alleles do not blend
C. F1 progeny (Red x White Snapdragon) are Pink
III. Incomplete Dominance
D. F1 progeny (I A I B) have AB sugar types
IV. Co-dominance
Choose the correct answer from the options given below:
F1 tall plants (A) are explained by the Law of Dominance. The reappearance of dwarf in F2 (B) confirms non-blending, the basis for the Law of Segregation. Pink Snapdragon (C) is incomplete dominance. AB blood type (D) shows co-dominance.
Question 366 of 519
π CLASS XII
Match List-I (Dihybrid Cross Observation) with List-II (Phenotypic Class Proportion):
List-I (F2 Phenotype)
List-II (Proportion in 9:3:3:1)
A. Round, Yellow (R_Y_)
I. 9/16
B. Wrinkled, Yellow (rrY_)
II. 3/16
C. Round, Green (R_yy)
III. 3/16
D. Wrinkled, Green (rryy)
IV. 1/16
Choose the correct answer from the options given below:
The F2 dihybrid phenotypic ratio 9:3:3:1 corresponds to the proportions 9/16 (A), 3/16 (B), 3/16 (C), and 1/16 (D), respectively, derived from the combination series (3:1) x (3:1).
Question 367 of 519
π CLASS XII
Match List-I (Linkage/Recombination Data) with List-II (Distance/Strength):
List-I (Genes in Drosophila)
List-II (Recombination/Linkage)
A. Yellow and white genes
I. 1.3% recombination (Very tightly linked)
B. White and miniature wing genes
II. 37.2% recombination (Loosely linked)
C. Linkage
III. Physical association of genes on a chromosome
D. Recombination Frequency
IV. Measure of distance between genes
Choose the correct answer from the options given below:
Yellow and white genes showed 1.3% recombination (A). White and miniature wing showed 37.2% recombination (B). Linkage (C) is the physical association of genes. Recombination frequency (D) measures the distance between genes.
Question 368 of 519
π CLASS XII
Match List-I (Genetic Term) with List-II (Explanation/Difference):
List-I
List-II
A. Inheritance
I. Process by which characters are passed from parent to progeny
B. Variation
II. Degree by which progeny differ from their parents
C. Genotype
III. Allelic composition (e.g., TT, Tt, tt)
D. Phenotype
IV. Descriptive appearance (e.g., Tall, Dwarf)
Choose the correct answer from the options given below:
Inheritance is the passing of characters from parent to progeny. Variation is the degree of difference in progeny from parents. Genotype is the allelic composition. Phenotype is the descriptive appearance.
Question 369 of 519
π CLASS XII
Match List-I (Honey Bee Sex Status) with List-II (Chromosome Count):
List-I (Sex)
List-II (Haploidy/Diploidy)
A. Female (Queen/Worker)
I. Diploid (32 chromosomes)
B. Male (Drone)
II. Haploid (16 chromosomes)
C. Male gamete production
III. Mitosis
D. Female development
IV. From union of sperm and egg (fertilized egg)
Choose the correct answer from the options given below:
Females are diploid (32 chromosomes). Males are haploid (16 chromosomes). Males produce sperm via mitosis. Females develop from a fertilized egg.
Question 370 of 519
π CLASS XII
Match List-I (Genotype) with List-II (Phenotype in ABO Blood Grouping):
List-I (Genotype)
List-II (Phenotype)
A. $I^A I^A$
I. A
B. $I^B i$
II. B
C. $I^A I^B$
III. AB
D. $i i$
IV. O
Choose the correct answer from the options given below:
$I^A I^A$ yields A blood group. $I^B i$ yields B blood group (as $I^B$ is dominant over $i$). $I^A I^B$ yields AB blood group (Co-dominance). $i i$ yields O blood group.