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Principles of Inheritance and Variation: Class-XII


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MCQs on Principles of Inheritance and Variation: Class-XII for NEET Practice


The mutation in sickle-cell anaemia involves the substitution of:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • Valine by Glutamic acid at the 6th position of the beta globin chain
  • Glutamic acid by Valine at the 6th position of the beta globin chain
  • Valine by Glutamic acid at the 6th position of the alpha globin chain
  • Glutamic acid by Valine at the 6th position of the alpha globin chain
  • Correct Option: B  [ Glutamic acid by Valine at the 6th position of the beta globin chain ]

    Remark: The defect is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin molecule.

The single base substitution at the sixth codon of the beta globin gene that causes sickle-cell anaemia is:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • GAG to GUG
  • GUG to GAG
  • GAA to GUA
  • GUC to GAC
  • Correct Option: A  [ GAG to GUG ]

    Remark: The substitution of the amino acid in the globin protein results from a single base substitution at the sixth codon of the beta globin gene, changing it from GAG to GUG.

Phenylketonuria is an inborn error of metabolism inherited as an autosomal recessive trait. It is caused by the lack of an enzyme that converts:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • Tyrosine into Phenylalanine
  • Phenylalanine into Tyrosine
  • Tryptophan into Melatonin
  • Glutamic acid into Valine
  • Correct Option: B  [ Phenylalanine into Tyrosine ]

    Remark: In phenylketonuria, the affected individual lacks an enzyme that converts the amino acid phenylalanine into tyrosine, leading to its accumulation and conversion into phenylpyruvic acid.

Thalassemia is different from sickle-cell anaemia because it is a:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • Qualitative problem of synthesising an incorrectly functioning globin
  • Quantitative problem of synthesising too few globin molecules
  • Problem related to blood clotting factors
  • Disorder caused by a viral infection
  • Correct Option: B  [ Quantitative problem of synthesising too few globin molecules ]

    Remark: Thalassemia differs from sickle-cell anaemia in that the former is a quantitative problem of synthesising too few globin molecules, while the latter is a qualitative problem of synthesising an incorrectly functioning globin.

Failure of segregation of chromatids during the cell division cycle, resulting in the gain or loss of a chromosome, is called:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • Polyploidy
  • Aneuploidy
  • Translocation
  • Inversion
  • Correct Option: B  [ Aneuploidy ]

    Remark: Failure of segregation of chromatids during the cell division cycle results in the gain or loss of a chromosome(s), a condition called aneuploidy.

Down’s syndrome is caused by the presence of an additional copy of which chromosome?

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • Chromosome 21
  • Chromosome 18
  • X chromosome
  • Y chromosome
  • Correct Option: A  [ Chromosome 21 ]

    Remark: The cause of Down’s syndrome is the presence of an additional copy of chromosome number 21 (trisomy of 21). The disorder was first described by Langdon Down in 1866.

Klinefelter’s syndrome is a genetic disorder caused by:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • The absence of an X chromosome (X0)
  • The presence of an additional copy of chromosome 21
  • The presence of an additional copy of an X chromosome (XXY)
  • The presence of an additional Y chromosome (XYY)
  • Correct Option: C  [ The presence of an additional copy of an X chromosome (XXY) ]

    Remark: Klinefelter’s syndrome is caused by the presence of an additional copy of an X-chromosome, resulting in a karyotype of 47, XXY.

Turner’s syndrome is caused by the absence of one of the X chromosomes, resulting in a karyotype of:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • 47, XXY
  • 47, Trisomy 21
  • 45, X0
  • 46, XY
  • Correct Option: C  [ 45, X0 ]

    Remark: Turner’s syndrome is caused by the absence of one of the X chromosomes, leading to a karyotype of 45 with X0.

A cross between two tall pea plants resulted in offspring of which some were dwarf. The genotype of the parent plants is:

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • TT x TT
  • TT x Tt
  • Tt x Tt
  • TT x tt
  • Correct Option: C  [ Tt x Tt ]

    Remark: The appearance of the recessive dwarf phenotype (tt) in the offspring indicates that both parents must have carried the recessive allele (t). Since the parents were tall (dominant phenotype), they must both be heterozygous (Tt). A Tt x Tt cross yields a genotypic ratio of 1:2:1 and a phenotypic ratio of 3:1.

If a colour-blind man marries a woman who is a carrier for colour blindness, what is the probability that their son will be colour-blind?

[Principles-of-Inheritance-and-Variation] [class-xii ]

  • 0%
  • 25%
  • 50%
  • 100%
  • Correct Option: C  [ 50% ]

    Remark: The son of a woman who carries the gene has a 50 per cent chance of being colour blind. The man's genotype is XcY and the woman's is XhX. A son receives Y from the father and either Xh or X from the mother, giving a 50% chance of being XhY (colour-blind).